2x^(1/2)+5x^(1/4)-3=0

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Solution for 2x^(1/2)+5x^(1/4)-3=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

2*x^(1/2)+5*x^(1/4)-3 = 0

t_1 = x^(1/4)

2*t_1^2+5*t_1^1-3 = 0

2*t_1^2+5*t_1-3 = 0

DELTA = 5^2-(-3*2*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-5)/(2*2) or t_1 = (-49^(1/2)-5)/(2*2)

t_1 = 1/2 or t_1 = -3

t_1 = -3

x^(1/4)+3 = 0

1*x^(1/4) = -3 // : 1

x^(1/4) = -3

( -3 < 0 i 1/4 in (0:1) ) => x naleu017Cy do O

t_1 = 1/2

x^(1/4)-1/2 = 0

1*x^(1/4) = 1/2 // : 1

x^(1/4) = 1/2

x^(1/4) = 1/2 // ^ 4

x = 1/16

x = 1/16

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